(广义)线性模型|STAT3030/STATS5019 /STAT 504/STA600/Stat 539/STAT*6802/ST411/STAT 7430/SS 3860B(Generalized) Linear Models代写

0

这是一份贝叶斯统计推断作业代写的成功案

(广义)线性模型|STAT3030/STATS5019 /STAT 504/STA600/Stat 539/STAT*6802/ST411/STAT 7430/SS 3860B(Generalized) Linear Models代写



$$
\mu_{t}=\sum_{i} \beta_{i} x_{i t}
$$
However, this yields a conditional model of the form
$$
\mu_{t \mid t-1}=\rho\left(y_{t-1}-\sum_{i} \beta_{i} x_{i, t-1}\right)+\sum_{i} \beta_{i} x_{i t}
$$
This may also be written
$$
\mu_{t \mid t-1}-\sum_{i} \beta_{i} x_{i t}=\rho\left(y_{t-1}-\sum_{i} \beta_{i} x_{i, t-1}\right)
$$



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STA 144/STAT 451/STAT 506/STA 317 COURSE NOTES :

where, again, $K$ is the unknown asymptotic maximum value. And again, we can obtain a linear structure, this time for a complementary log log link:
$$
\log \left[-\log \left(\frac{K-y}{K}\right)\right]=\log (\alpha)+\beta t
$$
We can use the same iterative procedure as before.





广义线性模型 | Generalized Linear Models代写 STAT 504代考

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这是一份psu宾夕法尼亚州立大学 STAT 504作业代写的成功案

(广义) 线性楛梨 | (Generalized) Linear Models代写 STAT 504代考
问题 1.

$$
f(y ; \theta)=\exp [y \theta-b(\theta)+c(y)]
$$
the conjugate distribution for the random parameter is
$$
p(\theta ; \zeta, \gamma)=\exp [\zeta \theta-\gamma b(\theta)+s(\zeta, \gamma)]
$$


证明 .

where $s(\zeta, \gamma)$ is a term not involving $\theta$. This conjugate is also a member of the exponential family. The resulting compound distribution, for $n$ observations, is
$$
f(y ; \zeta, \gamma)=\exp [s(\zeta, \gamma)+c(y)-s(\zeta+y, \gamma+n)]
$$
This is not generally a member of the exponential family.

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STAT 504 COURSE NOTES :


$$
y=K \frac{\alpha \mathrm{e}^{\beta t}}{1+\alpha \mathrm{e}^{\beta t}}
$$
where $K$ is the asymptotic maximum value of the response.
We can transform this to a linear structure by using a logit link:
$$
\log \left(\frac{y}{K-y}\right)=\log (\alpha)+\beta t
$$