这是一份kcl伦敦大学学院 6CCM326A作业代写的成功案
问题 1.
PROOF: Using obstruction theory one sees there is a unique extension $f$ in
$$
\text { localization } \times \text { identity } Y \times Y^{\prime}
$$
证明 .
Thus we have natural maps
$$
\widehat{X}{S} \rightarrow X{A}
$$
which imply a map
$$
\underset{\vec{s}}{\lim } \widehat{X}{S} \stackrel{A}{\rightarrow} X{A}
$$
6CCM327A COURSE NOTES ：
$$
\text { image }\left(\pi_{k} X_{n-1} \rightarrow \pi_{k} Y_{n-1}\right)
$$
Then $a^{\prime}$ works for the new localization
$$
S^{k} \rightarrow S_{0}^{k} \stackrel{m}{\cong} S_{0}^{k}
$$
and $X_{n}=X_{n-1} / S^{k} \cong$ cofibre $a^{\prime}$ satisfies
$$
\left(X_{n}\right){0} \cong Y{n} .
$$