编程范式 Programming Paradigms COMP1009

这是一份nottingham诺丁汉大学COMP1009作业代写的成功案例

数据库和接口 Databases & Interfaces COMP1004

procedure PassResult(terminate: integer;
inp1, inp2, out2: channel; var done boolean);
var $y$ :ResultTypes;
count:integer;
passing : boolean;
begin
done: =false;
passing : =true;
count: =0 ;
while not done and (count<terminate) do
pol1
inpl?result(y) $\rightarrow$
if passing then begin
out2 ! result (y) ;
passing: = false
end $\mid$
inp2?result $(y) \rightarrow$
if passing then begin
out2 ! result ( $y)$;
passing: false
and $\mid$
inpl?complete $\rightarrow$
count: $=$ coun $t+1$;
if count=terminate then out 2 ! complete |
inp2?complete $\rightarrow$
count: =count $+1$;
If count werminate then out 2 ! complete |
inpl ?eos $\rightarrow$ done: = true
end ;



英国论文代写Viking Essay为您提供作业代写代考服务

COMP1009 COURSE NOTES :

If $r$ and $s$ are odd primes, then prime $p$ satisfies
$$
p \equiv 1(\bmod r) \equiv s-1(\bmod s)
$$
if $p$ is of the form
$$
p=u(r, s)+k r s
$$
where
$$
u(r, s)=\left(s^{r-1}-r^{x-1}\right) \bmod r s
$$
and $k$ is an integer.









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