The students are cultivated as high-quality innovative professionals. They are well developed in the
aspects of morality, intelligence, physique, and aesthetic. They possess the basic theoretical knowledge in
the fields of Materials Science and Physics，and are well trained in the applied research, technological
development, and engineering. They can research physical properties and laws of materials at the level of
molecule, atom and electron，and apply to develop new materials preparative technology，advanced
function materials and equipments. The graduates are expected to work in various industries, universities,
and research institutes in the fields of over function materials and the related (such as energy engineering,
electric power, etc.), engaging in product design, technological development, scientific research, and
management, and playing important and leading roles in the fields with international competitiveness and
innovation.
这是一份sydney悉尼大学PHYS3035/PHYS3935 的成功案例
$$
\varrho_{-}^{\prime}=\frac{\varrho}{\sqrt{1-\left(u-u_{\mathrm{e}}\right)^{2} / c^{2}}}=\varrho\left(1+\frac{1}{2 c^{2}}\left(u^{2}-2 u u_{\mathrm{e}}\right)\right),
$$
and for the lower section of windings, just above (1),
$$
\varrho_{-}^{\prime}=\frac{\varrho}{\sqrt{1-\left(u+u_{e}\right)^{2} / c^{2}}}=\varrho\left(1+\frac{1}{2 c^{2}}\left(u^{2}+2 u u_{e}\right)\right) \text {. }
$$
For the upper section of the coil containing $N$ wires , combiningand yields an excess of positive charges:
$$
\Delta Q_{+}^{\prime}=N \Delta q_{+}^{\prime}=\frac{N q u_{\mathrm{e}} u}{c^{2}} .
$$
For the lower section of windings (1), the combination of yields an excess of negative charges:
$$
\Delta Q_{-}^{\prime}=N \Delta q_{-}^{\prime}=-\frac{N q u_{\mathrm{e}} u}{c^{2}}
$$
PHYS3035/PHYS3935 COURSE NOTES ：
Derivation: Each end of the bar (or coil) produces a flux density $B_{t}=$ $\frac{\Phi}{4 \pi R^{2}}$ at the point of observation according. Only the difference of the two values is important, so that in the first principal orientation
$$
B=\frac{\phi}{4 \pi}\left(\frac{1}{(R-l / 2)^{2}}-\frac{1}{(R+1 / 2)^{2}}\right)
$$
When the distance $R$ is sufficiently large compared to the length $I$ of the bar or coil, we can neglect $P^{2}$ relative to $R^{2}$, and for the magnitude of $B$, we then obtain
$$
B=\frac{1}{2 \pi} \frac{\Phi l}{R^{3}}=\frac{\mu_{0}}{2 \pi} \frac{m}{R^{3}}
$$
Correspondingly, for the second principal orientation, we find
$$
B=\frac{\mu_{0}}{4 \pi} \frac{m^{3}}{R^{3}}
$$